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  4. A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are n × 10-1, when n = (Round off to the Nearest Integer). (Given: Atomic masses: C: 12.0 u, H: 1.0 u , N: 14.0 u , Br: 80.0 u ]

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Q. A reaction of 0.1 mole of Benzylamine with bromomethane gave 23 g of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $n \times 10^{-1}$, when n = (Round off to the Nearest Integer).
(Given : Atomic masses : $C : 12.0\, u, \,H : 1.0\, u ,\, N :\, 14.0\, u ,\, Br : 80.0\, u$ ]

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Solution:

Correct answer is '3'

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