A ray of light is incident at polarising angle such that its deviation is 24° , then angle of incidence is

Question

A ray of light is incident at polarising angle such that its deviation is 24° , then angle of incidence is (A)  24°  (B)  57°  (C)  66°  (D)  90°

Tardigrade Admin · Accepted Answer

Here, ip=r+δ <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/31e5959f70aed7051020a7f16a1c70c1-.png" /> ip=r+24...(i) Moreover, ip+r=90°...(ii) From Eqs. (i) and (ii), we get ip+(ip-24) =90° ⇒ ip =57°

Q. A ray of light is incident at polarising angle such that its deviation is $2 4^{\circ}$ , then angle of incidence is

$2 4^{\circ}$

$5 7^{\circ}$

$6 6^{\circ}$

$9 0^{\circ}$

Here, $i_{p} = r + δ$

$i_{p} = r + 24$ ...(i)
Moreover, $i_{p} + r = 9 0^{\circ}$ ...(ii)
From Eqs. (i) and (ii), we get
$i_{p} + (i_{p} - 24) = 9 0^{\circ}$
$\Rightarrow i_{p} = 5 7^{\circ}$

Q. A ray of light is incident at polarising angle such that its deviation is 24∘ , then angle of incidence is

24∘

57∘

66∘

90∘