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Q. A ray of light is incident at polarising angle such that its deviation is $ 24^{\circ} $ , then angle of incidence is

MHT CETMHT CET 2009Wave Optics

Solution:

Here, $i_{p}=r+\delta$
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$i_{p}=r+24$...(i)
Moreover, $i_{p}+r=90^{\circ}$...(ii)
From Eqs. (i) and (ii), we get
$i_{p}+\left(i_{p}-24\right) =90^{\circ}$
$\Rightarrow i_{p} =57^{\circ}$