A quality factor of LCR factor circuit having resistance R and inductance L at resonance frequency (to) is given by :

Question

A quality factor of LCR factor circuit having resistance R and inductance L at resonance frequency (to) is given by : (A)  ( (ω L/R) )2  (B)  ( (Rω /L) )2  (C)  (Rω /L)  (D)  (ω L/R)

Tardigrade Admin · Accepted Answer

The potential difference developed across the inductance is =i ω L The emf applied is =iR Hence, quality factor Q=(Potential difference/Applied emf)=(i ω L/iR)=(ω L/R)

Q. A quality factor of LCR factor circuit having resistance R and inductance L at resonance frequency (to) is given by :

$(\frac{ω L}{R})^{2}$

$(\frac{R ω}{L})^{2}$

$\frac{R ω}{L}$

$\frac{ω L}{R}$

The potential difference developed across the inductance is $= i ω L$ The emf applied is $= i R$ Hence, quality factor $Q = \frac{P o t e n t ia l d i ff ere n ce}{A ppl i e d e m f} = \frac{i ω L}{i R} = \frac{ω L}{R}$

Q. A quality factor of LCR factor circuit having resistance R and inductance L at resonance frequency (to) is given by :

(RωL​)2

(LRω​)2

LRω​

RωL​

The potential difference developed across the inductance is =iωL The emf applied is =iR Hence, quality factor Q=AppliedemfPotentialdifference​=iRiωL​=RωL​

$(\frac{ω L}{R})^{2}$

$(\frac{R ω}{L})^{2}$

$\frac{R ω}{L}$

$\frac{ω L}{R}$

The potential difference developed across the inductance is $= i ω L$ The emf applied is $= i R$ Hence, quality factor $Q = \frac{P o t e n t ia l d i ff ere n ce}{A ppl i e d e m f} = \frac{i ω L}{i R} = \frac{ω L}{R}$