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Q.
A quality factor of LCR factor circuit having resistance R and inductance L at resonance frequency (to) is given by :
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Solution:
The potential difference developed across the inductance is $ =i\,\omega \,L $ The emf applied is $ =iR $ Hence, quality factor $ Q=\frac{Potential\,difference}{Applied\,emf}=\frac{i\,\omega \,L}{iR}=\frac{\omega L}{R} $