A purse contains 4 copper coins and 3 silver coins and another purse consist 6 copper and 2 silver coins. A coin is taken out from any purse. The probability that it is a copper coin, is

Question

A purse contains 4 copper coins and 3 silver coins and another purse consist 6 copper and 2 silver coins. A coin is taken out from any purse. The probability that it is a copper coin, is (A) (7/21) (B) (23/66) (C) (37/56) (D) (1/4)

Tardigrade Admin · Accepted Answer

Required probability= (1/2) × (4/7) + (1/2) × (6/8) = (37/56)

Q. A purse contains $4$ copper coins and $3$ silver coins and another purse consist $6$ copper and $2$ silver coins. A coin is taken out from any purse. The probability that it is a copper coin, is

$\frac{7}{21}$

$\frac{23}{66}$

$\frac{37}{56}$

$\frac{1}{4}$

Required probability $= \frac{1}{2} \times \frac{4}{7} + \frac{1}{2} \times \frac{6}{8} = \frac{37}{56}$

Q. A purse contains 4 copper coins and 3 silver coins and another purse consist 6 copper and 2 silver coins. A coin is taken out from any purse. The probability that it is a copper coin, is

217​

6623​

5637​

41​