Question

A purse contains $4$ copper coins and $3$ silver coins and another purse consist $6$ copper and $2$ silver coins. A coin is taken out from any purse. The probability that it is a copper coin, is

• A. $\frac{7}{21}$
• B. $\frac{23}{66}$
• C. $\frac{37}{56}$
• D. $\frac{1}{4}$

Answer 1

Answer: (C)

Required probability$= \frac{1}{2} \times \frac{4}{7} + \frac{1}{2} \times \frac{6}{8} = \frac{37}{56}$