A proton of mass "m" and charge ''e" is fired parallel to a Uniform magnetic, field of induction B. The radius of curvature of the path of the particel in the field is

Question

A proton of mass "m" and charge ''e" is fired parallel to a Uniform magnetic, field of induction B. The radius of curvature of the path of the particel in the field is (A) Be/mv (B) mv/Be (C) zero (D) infinity

Tardigrade Admin · Accepted Answer

F = q ( vec V × vec B ) θ=0° F =0 It will keep moving in its initial direction. So r=∞

Q. A proton of mass "m" and charge ''e" is fired parallel to a Uniform magnetic, field of induction B. The radius of curvature of the path of the particel in the field is

Be/mv

mv/Be

zero

infinity

$F = q (V \times B)$
$θ = 0^{\circ}$
$F = 0$
It will keep moving in its initial direction.
So $r = \infty$

Q. A proton of mass "m" and charge ''e" is fired parallel to a Uniform magnetic, field of induction B. The radius of curvature of the path of the particel in the field is

Be/mv

mv/Be

zero

infinity

F=q(V×B) θ=0∘ F=0 It will keep moving in its initial direction. So r=∞

$F = q (V \times B)$
$θ = 0^{\circ}$
$F = 0$
It will keep moving in its initial direction.
So $r = \infty$