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Q. A proton of mass "m" and charge ''e" is fired parallel to a Uniform magnetic, field of induction B. The radius of curvature of the path of the particel in the field is

Moving Charges and Magnetism

Solution:

$F = q (\vec{ V } \times \vec{ B })$
$\theta=0^{\circ} $
$F =0$
It will keep moving in its initial direction.
So $r=\infty$