A proton is accelerated through 225 V. Its de Broglie wavelength is

Question

A proton is accelerated through 225 V. Its de Broglie wavelength is (A) 0.1 nm (B) 0.2 nm (C) 0.3 nm (D) 0.4 nm

Tardigrade Admin · Accepted Answer

Energy it gains =225 eV λ=(h/m v)=(λ h/√2 m E)

Q. A proton is accelerated through $225 V$ . Its de Broglie wavelength is