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  4. A proton is accelerated through 225 V. Its de Broglie wavelength is

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Q. A proton is accelerated through $225 \,V$. Its de Broglie wavelength is

Dual Nature of Radiation and Matter

Solution:

Energy it gains $=225 \,eV$
$\lambda=\frac{h}{m v}=\frac{\lambda h}{\sqrt{2 m E}}$