A proton in a cyclotron changes its velocity from 30 kmh-1 north to 45 kmh-1 east in 20 s. What is the magnitude of average acceleration during the same?

Question

A proton in a cyclotron changes its velocity from 30 kmh-1 north to 45 kmh-1 east in 20 s. What is the magnitude of average acceleration during the same? (A) 2.5 kms-2 (B) 12.5 kms-2 (C) 22.5 kms-2 (D) 32.5 kms-2

Tardigrade Admin · Accepted Answer

Change in velocity =√(40)2+(30)2=50 kms -1 Average acceleration =(50/20)=2.5 kms -2 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7100ba49927e793e8a2a0cb4ffc67aec-.png" />

Q. A proton in a cyclotron changes its velocity from $30 km h^{- 1}$ north to $45 km h^{- 1}$ east in $20 s$ . What is the magnitude of average acceleration during the same?

$2.5 km s^{- 2}$

$12.5 km s^{- 2}$

$22.5 km s^{- 2}$

$32.5 km s^{- 2}$

Change in velocity $= (40)^{2} + (30)^{2} = 50 km s^{- 1}$
Average acceleration
$= \frac{50}{20} = 2.5 km s^{- 2}$

Q. A proton in a cyclotron changes its velocity from 30kmh−1 north to 45kmh−1 east in 20s. What is the magnitude of average acceleration during the same?

2.5kms−2

12.5kms−2

22.5kms−2

32.5kms−2