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Q.
A proton in a cyclotron changes its velocity from $30 kmh^{-1}$ north to $45 kmh^{-1}$ east in $20\, s$. What is the magnitude of average acceleration during the same?
Motion in a Plane
Solution:
Change in velocity $=\sqrt{(40)^{2}+(30)^{2}}=50 kms ^{-1}$
Average acceleration
$=\frac{50}{20}=2.5 kms ^{-2}$