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Q. A proton in a cyclotron changes its velocity from $30 kmh^{-1}$ north to $45 kmh^{-1}$ east in $20\, s$. What is the magnitude of average acceleration during the same?

Motion in a Plane

Solution:

Change in velocity $=\sqrt{(40)^{2}+(30)^{2}}=50 kms ^{-1}$
Average acceleration
$=\frac{50}{20}=2.5 kms ^{-2}$
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