A projectile is thrown into space so as to have a maximum possible horizontal range of 400 metres. Taking the point of projection as the origin, the co-ordinates of the point where the velocity of the projectile is minimum are

Question

A projectile is thrown into space so as to have a maximum possible horizontal range of 400 metres. Taking the point of projection as the origin, the co-ordinates of the point where the velocity of the projectile is minimum are (A) (400,100) (B) (200,100) (C) (400,200) (D) (200,200)

Tardigrade Admin · Accepted Answer

R max =400 m The velocity is minimum at the highest point ⇒ H arrow (R/2) R=4 H 400=4 × H H=100 m

Q. A projectile is thrown into space so as to have a maximum possible horizontal range of $400$ metres. Taking the point of projection as the origin, the co-ordinates of the point where the velocity of the projectile is minimum are

(400,100)

(200,100)

(400,200)

(200,200)

$R_{m a x} = 400 m$
The velocity is minimum at the highest point
$\Rightarrow H \to \frac{R}{2}$
$R = 4 H$
$400 = 4 \times H$
$H = 100 m$

Q. A projectile is thrown into space so as to have a maximum possible horizontal range of 400 metres. Taking the point of projection as the origin, the co-ordinates of the point where the velocity of the projectile is minimum are