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Tardigrade
Question
Physics
A primary cell has an e.rn.f. of 1.5 volt. When short-circuited it gives a current of 3 ampere. The internal resistance of the cell is
Q. A primary cell has an e.rn.f. of
1.5
volt. When short-circuited it gives a current of
3
ampere. The internal resistance of the cell is
952
178
Current Electricity
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A
4.5 ohm
25%
B
2 ohm
21%
C
0.5 ohm
44%
D
(1/45)ohm
10%
Solution:
r
=
E
/
I
=
1.5/3
=
0.5
o
hm