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  4. A primary cell has an e.rn.f. of 1.5 volt. When short-circuited it gives a current of 3 ampere. The internal resistance of the cell is

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Q. A primary cell has an e.rn.f. of $1.5$ volt. When short-circuited it gives a current of $3$ ampere. The internal resistance of the cell is

Current Electricity

Solution:

$r = E / I =1.5 / 3=0.5\, ohm$