A pressure of x dyne cm-2 is equivalent to

Question

A pressure of x dyne cm-2 is equivalent to (A)  ( (x/10) )Nm-2  (B)  ( (x/100) )Nm-2  (C)  10x Nm-2  (D)  ( (x/104) ) Nm-2

Tardigrade Admin · Accepted Answer

Dyne cm-2 can be converted into Nm-2 either using dimensions or remembering 1 dyne =10-5m (1 dyne/cm2)=(10-5/10-4)(N/m2)=10-1N/m2 x(dyne/cm2)=(x/10)(N/m2)

Q. A pressure of $x$ dyne $c m^{- 2}$ is equivalent to

$(\frac{x}{10}) N m^{- 2}$

$(\frac{x}{100}) N m^{- 2}$

$10 x N m^{- 2}$

$(\frac{x}{10 ^{4}}) N m^{- 2}$

Dyne $c m^{- 2}$ can be converted into
$N m^{- 2}$ either using dimensions or remembering 1 dyne
$= 10^{- 5} m$ $\frac{1 d y n e}{c m ^{2}} = \frac{10 ^{- 5}}{10 ^{- 4}} \frac{N}{m ^{2}} = 10^{- 1} N / m^{2}$
$x \frac{d y n e}{c m ^{2}} = \frac{x}{10} \frac{N}{m ^{2}}$

Q. A pressure of x dyne cm−2 is equivalent to

(10x​)Nm−2

(100x​)Nm−2

10xNm−2

(104x​)Nm−2