Question

A pressure of $ x $ dyne $ c{{m}^{-2}} $ is equivalent to

• A. $ \left( \frac{x}{10} \right)N{{m}^{-2}} $
• B. $ \left( \frac{x}{100} \right)N{{m}^{-2}} $
• C. $ 10x\,N{{m}^{-2}} $
• D. $ \left( \frac{x}{{{10}^{4}}} \right)\,N{{m}^{-2}} $

Answer 1

Answer: (A)

Dyne $ c{{m}^{-2}} $ can be converted into
$ N{{m}^{-2}} $ either using dimensions or remembering 1 dyne
$={{10}^{-5}}m $ $ \frac{1\,dyne}{c{{m}^{2}}}=\frac{{{10}^{-5}}}{{{10}^{-4}}}\frac{N}{{{m}^{2}}}={{10}^{-1}}N/{{m}^{2}} $
$ x\frac{dyne}{c{{m}^{2}}}=\frac{x}{10}\frac{N}{{{m}^{2}}} $