A precipitate of AgCl is formed when equal volumes of the following are mixed. [KS for AgCl = 10-10]

Question

A precipitate of AgCl is formed when equal volumes of the following are mixed. [KS for AgCl = 10-10] (A) 10-4 M AgNO3 and 10-7 M HCl (B) 10-5 M AgNO3 and 10-6 M HCl (C) 10-5 M AgNO3 and 10-4 M HCl (D) 10-6 M AgNO3 and 10-6 M HCl

Tardigrade Admin · Accepted Answer

A precipitate of AgCl is formed when equal volumes of 10-5 M Ag NO 3 and 10-5 M HCl are mixed, because ionic product will be 10-9 which is greater than Ks p(10-10) . For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product.

Q. A precipitate of $A g Cl$ is formed when equal volumes of the following are mixed. $[K_{S} f or A g Cl = 1 0^{- 10}]$

$1 0^{- 4} M A g N O_{3}$ and $1 0^{- 7} M H Cl$

$1 0^{- 5} M A g N O_{3}$ and $1 0^{- 6} M H Cl$

$1 0^{- 5} M A g N O_{3}$ and $1 0^{- 4} M H Cl$

$1 0^{- 6} M A g N O_{3}$ and $1 0^{- 6} M H Cl$

Q. A precipitate of AgCl is formed when equal volumes of the following are mixed. [KS​forAgCl=10−10]

10−4MAgNO3​ and 10−7MHCl

10−5MAgNO3​ and 10−6MHCl

10−5MAgNO3​ and 10−4MHCl

10−6MAgNO3​ and 10−6MHCl

A precipitate of AgCl is formed when equal volumes of 10−5MAgNO3​ and 10−5MHCl are mixed, because ionic product will be 10−9 which is greater than Ksp​(10−10). For the precipitation of an electrolyte, it is necessary that the ionic product must exceed its solubility product.

Q. A precipitate of $A g Cl$ is formed when equal volumes of the following are mixed. $[K_{S} f or A g Cl = 1 0^{- 10}]$

$1 0^{- 4} M A g N O_{3}$ and $1 0^{- 7} M H Cl$

$1 0^{- 5} M A g N O_{3}$ and $1 0^{- 6} M H Cl$

$1 0^{- 5} M A g N O_{3}$ and $1 0^{- 4} M H Cl$

$1 0^{- 6} M A g N O_{3}$ and $1 0^{- 6} M H Cl$