Question

A positron is emitted from ${}_{11}^{23}Na$. The ratio of the atomic
mass and atomic number of the resulting nuclide is

• A. 22/10
• B. 22/11
• C. 23/10
• D. 23/12

Answer 1

Answer: (C)

The required nuclear reaction is
${}_{11}^{}N{a}^{23}⟶{}_{+1}^{}{e}^0+{}_{10}^{}N{a}^{23}$