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Q. A positron is emitted from $^{23}_{11}Na$. The ratio of the atomic
mass and atomic number of the resulting nuclide is

IIT JEEIIT JEE 2007

Solution:

The required nuclear reaction is
$^{}_{11}Na^{23} \longrightarrow \,{}^{}_{+1}e^0 + \,{}^{}_{10}Na^{23}$