Question

A positive point charge is placed at $P$ in front of an earthed metal sheet $S$ . $Q$ and $R$ are two points between $P$ and $S$ as shown in the figure. If the electric field strength at $Q$ and $R$ are respectively ${\text{E}}_{\text{Q}}$ , ${\text{E}}_{\text{R}}$ and potential at $Q$ and $R$ are respectively ${\text{V}}_{\text{Q}}$ , ${\text{V}}_{\text{R}}$ . Then

• A. ${\text{E}}_{\text{Q}}={\text{ E}}_{\text{R}}$
• B. ${\text{E}}_{\text{Q}}<{\text{ E}}_{\text{R}}$
• C. ${\text{V}}_{\text{Q}}>{\text{V}}_{\text{R}}$
• D. ${\text{V}}_{\text{Q}}<{\text{ V}}_{\text{R}}$

Answer 1

Answer: (C)

As we are are moving away from $P$ toward sheet $S$ spacing between electric lines of force is increasing. $\therefore E_R<E_Q$ In direction of electric field potential decreases. $\therefore V_R<V_Q$