A polarized light of intensity I0 is passed through another polarizer whose pass axis makes an angle of 60° with the pass axis of the former. What is the intensity of emergent polarized light from second polarizer

Question

A polarized light of intensity I0 is passed through another polarizer whose pass axis makes an angle of 60° with the pass axis of the former. What is the intensity of emergent polarized light from second polarizer (A) I = Io (B) I = I 0 / 6 (C) I = I 0 / 5 (D) I 0 / 4

Tardigrade Admin · Accepted Answer

By Malus law, I=I0 cos 2 θ (I = Intensity of emergent polarized light) where θ=60°, I =? =I0 × cos 2 60° (I0 Intensity passed through polariser =I0 ×((1/2))2=(I0/4)

Q. A polarized light of intensity $I_{0}$ is passed through another polarizer whose pass axis makes an angle of $60^{\circ}$ with the pass axis of the former. What is the intensity of emergent polarized light from second polarizer

$I = I_{o}$

$I = I_{0} /6$

$I = I_{0} /5$

$I_{0} /4$

By Malus law, $I = I_{0} cos^{2} θ$
(I = Intensity of emergent polarized light)
where $θ = 6 0^{\circ}, I = ?$
$= I_{0} \times cos^{2} 6 0^{\circ}$
$(I_{0}$ Intensity passed through polariser
$= I_{0} \times (\frac{1}{2})^{2} = \frac{I _{0}}{4}$

Q. A polarized light of intensity I0​ is passed through another polarizer whose pass axis makes an angle of 60∘ with the pass axis of the former. What is the intensity of emergent polarized light from second polarizer

I=Io​

I=I0​/6

I=I0​/5

I0​/4