Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A polarized light of intensity $I_0$ is passed through another polarizer whose pass axis makes an angle of ${60}^\circ$ with the pass axis of the former. What is the intensity of emergent polarized light from second polarizer

KCETKCET 2014Wave Optics

Solution:

By Malus law, $I=I_{0} \cos ^{2} \theta$
(I = Intensity of emergent polarized light)
where $\theta=60^{\circ}, I =?$
$=I_{0} \times \cos ^{2} 60^{\circ}$
$(I_{0}$ Intensity passed through polariser
$=I_{0} \times\left(\frac{1}{2}\right)^{2}=\frac{I_{0}}{4}$