A player caught a cricket ball of mass 150 g moving at the rate of 20 text ms-1 . If the catching process be completed in 0.1 s , the force of the blow exerted by the ball on the hands of the player is:

Question

A player caught a cricket ball of mass 150 g moving at the rate of 20 text ms-1 . If the catching process be completed in 0.1 s , the force of the blow exerted by the ball on the hands of the player is: (A) 0.3 N (B) 30 N (C) 300 N (D) 3000 N

Tardigrade Admin · Accepted Answer

Force, F=(m(u-v)/t) =(150× 10-3(20-0)/0.1) =30N

Q. A player caught a cricket ball of mass $150 g$ moving at the rate of $20 m s^{- 1}$ . If the catching process be completed in $0.1 s$ , the force of the blow exerted by the ball on the hands of the player is:

0.3 N

30 N

300 N

3000 N

3N

Force, $F = \frac{m ( u - v )}{t}$
$= \frac{150 \times 10 ^{- 3} ( 20 - 0 )}{0.1}$
$= 30 N$

Q. A player caught a cricket ball of mass 150g moving at the rate of 20ms−1 . If the catching process be completed in 0.1s , the force of the blow exerted by the ball on the hands of the player is: