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Q. A player caught a cricket ball of mass $ 150\, g $ moving at the rate of $ 20\text{ }m{{s}^{-1}} $ . If the catching process be completed in $ 0.1\, s $ , the force of the blow exerted by the ball on the hands of the player is:

KEAMKEAM 2005

Solution:

Force, $ F=\frac{m(u-v)}{t} $
$ =\frac{150\times {{10}^{-3}}(20-0)}{0.1} $
$ =30N $