A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to :

Question

A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to : (A) 150 N (B) 3 N (C) 30 N (D) 300 N

Tardigrade Admin · Accepted Answer

This is the question based on impulse-momentum theorem.

∣ F .Δ t ∣ =

| change in momentum|

\Rightarrow F \times 0.1 = ∣ p_{f} - p_{i} ∣

As the ball will stop after catching;

p_{i} = m v_{i} = 0.15 \times 20 = 3, p_{f} = 0

\Rightarrow F \times 0.1 = 3 \Rightarrow F = 30 N

Q. A player caught a cricket ball of mass $150 g$ moving at a rate of $20 m / s$ . If the catching process is completed in $0.1 s$ , the force of the blow exerted by the ball on the hand of the player is equal to :

$150 N$

$3 N$

$30 N$

$300 N$

This is the question based on impulse-momentum theorem.
$∣ F .Δ t ∣ =$ | change in momentum|
$\Rightarrow F \times 0.1 = ∣ p_{f} - p_{i} ∣$
As the ball will stop after catching;
$p_{i} = m v_{i} = 0.15 \times 20 = 3, p_{f} = 0$
$\Rightarrow F \times 0.1 = 3 \Rightarrow F = 30 N$

Q. A player caught a cricket ball of mass 150g moving at a rate of 20m/s. If the catching process is completed in 0.1s, the force of the blow exerted by the ball on the hand of the player is equal to :

150N

3N

30N

300N