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  4. A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to :

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Q. A player caught a cricket ball of mass $150\, g$ moving at a rate of $20\, m/s$. If the catching process is completed in $0.1\,s$, the force of the blow exerted by the ball on the hand of the player is equal to :

AIEEEAIEEE 2006Laws of Motion

Solution:

This is the question based on impulse-momentum theorem.
$\left|F . \Delta t\right|=$ | change in momentum|
$\Rightarrow F \times 0.1=\left|p_{f} -p_{i}\right|$
As the ball will stop after catching;
$p_{i}=mv_{i}=0.15 \times20=3, p_{f} =0$
$\Rightarrow F \times 0.1=3 \Rightarrow F=30 \,N$