A player catches a cricket ball of mass 0.15 kg moving with a speed of 20 ms-1 . The process of catching is completed in s. The average force exerted by the player is:

Question

A player catches a cricket ball of mass 0.15 kg moving with a speed of 20 ms-1 . The process of catching is completed in s. The average force exerted by the player is: (A) 0.3 N (B) 30 N (C) 3 N (D) 0.03 N

Tardigrade Admin · Accepted Answer

M =150 g v =20 m / s t =0.1 s a =( v - u ) / t =(20) / 0.1 =200 m f = ma =150 × 200 =30000 / 1000 =30 N

Q. A player catches a cricket ball of mass 0.15 kg moving with a speed of $20 m s^{- 1}$ . The process of catching is completed in s. The average force exerted by the player is:

0.3 N

30 N

3 N

0.03 N

$M = 150 g$
$v = 20 m / s$
$t = 0.1 s$
$a = (v - u) / t$
$= (20) /0.1$
$= 200 m$
$f = ma$
$= 150 \times 200$
$= 30000/1000$
$= 30 N$

Q. A player catches a cricket ball of mass 0.15 kg moving with a speed of 20ms−1 . The process of catching is completed in s. The average force exerted by the player is:

0.3 N

30 N

3 N

0.03 N

M=150g v=20m/s t=0.1s a=(v−u)/t =(20)/0.1 =200m f=ma =150×200 =30000/1000 =30N

Q. A player catches a cricket ball of mass 0.15 kg moving with a speed of $20 m s^{- 1}$ . The process of catching is completed in s. The average force exerted by the player is:

$M = 150 g$
$v = 20 m / s$
$t = 0.1 s$
$a = (v - u) / t$
$= (20) /0.1$
$= 200 m$
$f = ma$
$= 150 \times 200$
$= 30000/1000$
$= 30 N$