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Q. A player catches a cricket ball of mass 0.15 kg moving with a speed of $ 20\,m{{s}^{-1}} $ . The process of catching is completed in s. The average force exerted by the player is:

JIPMERJIPMER 1995

Solution:

$M =150 g$
$v =20 m / s$
$t =0.1 s$
$a =( v - u ) / t$
$=(20) / 0.1$
$=200 m$
$f = ma$
$=150 \times 200$
$=30000 / 1000$
$=30 N$