A plane is flying horizontally at 98m/s and releases an object which reaches the ground in 10 sec. The angle made by object while hitting the ground is :

Question

A plane is flying horizontally at 98m/s and releases an object which reaches the ground in 10 sec. The angle made by object while hitting the ground is : (A) 55°  (B) 45°  (C) 60°  (D) 75°

Tardigrade Admin · Accepted Answer

horizontal component of velocity of object VH=98m/s And vertical component vv=0+gt =9.8× 10=98m/s as VH=vv so angle made by object while hitting the ground =45° tanθ =(vv/vH)=1⇒ θ =45°

Q. A plane is flying horizontally at $98 m / s$ and releases an object which reaches the ground in $10$ sec. The angle made by object while
hitting the ground is :

$5 5^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$7 5^{\circ}$

horizontal component of velocity of object
$V_{H} = 98 m / s$
And vertical component $v_{v} = 0 + g t$
$= 9.8 \times 10 = 98 m / s$
as $V_{H} = v_{v}$
so angle made by object while hitting the ground $= 4 5^{\circ}$
$t an θ = \frac{v _{v}}{v _{H}} = 1 \Rightarrow θ = 4 5^{\circ}$

Q. A plane is flying horizontally at 98m/s and releases an object which reaches the ground in 10 sec. The angle made by object while hitting the ground is :

55∘

45∘

60∘

75∘