A plane is flying horizontally at 98 m s-1 and releases an object which reaches the ground in 10 s. The angle made by it while hitting the ground is

Question

A plane is flying horizontally at 98 m s-1 and releases an object which reaches the ground in 10 s. The angle made by it while hitting the ground is (A) 55° (B) 45° (C) 60° (D) 75°

Tardigrade Admin · Accepted Answer

The angle made by the object while hitting the ground is tan β = (gt/u) = (9.8 × 10/98) = 1 β = tan-1(1) = 45Â°

Q. A plane is flying horizontally at $98 m s^{- 1}$ and releases an object which reaches the ground in 10 s. The angle made by it while hitting the ground is

55°

45°

60°

75°

The angle made by the object while hitting the ground is
$tan β = \frac{g t}{u} = \frac{9.8 \times 10}{98} = 1$
$β = tan^{- 1} (1)$
= 45°

Q. A plane is flying horizontally at 98ms−1 and releases an object which reaches the ground in 10 s. The angle made by it while hitting the ground is

55°

45°

60°

75°

The angle made by the object while hitting the ground is tanβ=ugt​=989.8×10​=1 β=tan−1(1) = 45°

Q. A plane is flying horizontally at $98 m s^{- 1}$ and releases an object which reaches the ground in 10 s. The angle made by it while hitting the ground is

The angle made by the object while hitting the ground is
$tan β = \frac{g t}{u} = \frac{9.8 \times 10}{98} = 1$
$β = tan^{- 1} (1)$
= 45°