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Q. A plane is flying horizontally at $98\, m\, s^{-1}$ and releases an object which reaches the ground in 10 s. The angle made by it while hitting the ground is

JIPMERJIPMER 2010Motion in a Plane

Solution:

The angle made by the object while hitting the ground is
$\tan \, \beta = \frac{gt}{u} = \frac{9.8 \times 10}{98} = 1$
$\beta = \tan^{-1}(1)$
= 45°