A photon of energy 6 eV is incident on a metal surface whose work function is 2 eV. The minimum reverse potential to be applied for stopping the emission of electrons is

Question

A photon of energy 6 eV is incident on a metal surface whose work function is 2 eV. The minimum reverse potential to be applied for stopping the emission of electrons is (A) 2 volt (B) 4 volt (C) 6 volt (D) 8 volt

Tardigrade Admin · Accepted Answer

According to Einstein's photoelectric equation
Incident energy = Work function + Maximum kinetic energy of photoelectron

h υ = W_{0} + K_{ma x}

Substituting the given values, we get

6 e V = 2 e V + K_{ma x}

or

K_{ma x} = 4 e V

Stopping potential is

4 V

Q. A photon of energy $6 e V$ is incident on a metal surface whose work function is $2 e V$ . The minimum reverse potential to be applied for stopping the emission of electrons is

$2$ volt

$4$ volt

$6$ volt

$8$ volt

According to Einstein's photoelectric equation
Incident energy = Work function + Maximum kinetic energy of photoelectron
$h υ = W_{0} + K_{ma x}$
Substituting the given values, we get
$6 e V = 2 e V + K_{ma x}$
or $K_{ma x} = 4 e V$
Stopping potential is $4 V$

Q. A photon of energy 6eV is incident on a metal surface whose work function is 2eV. The minimum reverse potential to be applied for stopping the emission of electrons is

2 volt

4 volt

6 volt

8 volt