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  4. A photon of energy 6 eV is incident on a metal surface whose work function is 2 eV. The minimum reverse potential to be applied for stopping the emission of electrons is

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Q. A photon of energy $6 \,eV$ is incident on a metal surface whose work function is $2 \,eV$. The minimum reverse potential to be applied for stopping the emission of electrons is

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Solution:

According to Einstein's photoelectric equation
Incident energy = Work function + Maximum kinetic energy of photoelectron
$h\upsilon=W_{0}+K_{max}$
Substituting the given values, we get
$6\,eV=2\,eV+K_{max}$
or $K_{max}=4\,eV$
Stopping potential is $4 V$