A person swims in a river aiming to reach exactly on the opposite point on the bank of a river. His speed of swimming is 0.5 m/s at an angle of 120º with the direction of flow of water. The speed of water is

Question

A person swims in a river aiming to reach exactly on the opposite point on the bank of a river. His speed of swimming is 0.5 m/s at an angle of 120º with the direction of flow of water. The speed of water is (A) 1.0 m/s (B) 0.5 m/s (C) 0.25 m/s (D) 0.43 m/s

Tardigrade Admin · Accepted Answer

Let the speed of water =u Speed of swimmer =v=0.5 m/sec Angle between =v and =u is 120Â°. Then sin θ=( vecu/ vecv) ⇒ (u/0.5)=(1/2) or u=0.25 ms-1

Q. A person swims in a river aiming to reach exactly on the opposite point on the bank of a river. His speed of swimming is $0.5 m / s$ at an angle of $12 0^{º}$ with the direction of flow of water. The speed of water is

$1.0 m / s$

$0.5 m / s$

$0.25 m / s$

$0.43 m / s$

Let the speed of water $= u$
Speed of swimmer $= v = 0.5 m / sec$
Angle between $= v$ and $= u$ is $12 0^{°}$ . Then
$s in θ = \frac{u}{v} \Rightarrow \frac{u}{0.5} = \frac{1}{2} or u = 0.25 m s^{- 1}$

Q. A person swims in a river aiming to reach exactly on the opposite point on the bank of a river. His speed of swimming is 0.5m/s at an angle of 120º with the direction of flow of water. The speed of water is

1.0m/s

0.5m/s

0.25m/s

0.43m/s