A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 m / s 2 will be N. [ g =10 m / s 2]

Question

A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 m / s 2 will be N. [ g =10 m / s 2] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

When lift is at rest N = mg ⇒ 60 × 10=600 N When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction

N prime= M ( g - a ) ⇒ 60(10-1.8) N prime ⇒ 492 N

Q. A person standing on a spring balance inside a stationary lift measures $60 k g$ . The weight of that person if the lift descends with uniform downward acceleration of $1.8 m / s^{2}$ will be $N$ . $[g = 10 m / s^{2}]$

When lift is at rest
$N = m g$
$\Rightarrow 60 \times 10 = 600 N$
When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction

$N^{'} = M (g - a)$
$\Rightarrow 60 (10 - 1.8)$
$N^{'} \Rightarrow 492 N$

Q. A person standing on a spring balance inside a stationary lift measures 60kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8m/s2 will be N. [g=10m/s2]

When lift is at rest N=mg ⇒60×10=600N When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction N′=M(g−a) ⇒60(10−1.8) N′⇒492N

Q. A person standing on a spring balance inside a stationary lift measures $60 k g$ . The weight of that person if the lift descends with uniform downward acceleration of $1.8 m / s^{2}$ will be $N$ . $[g = 10 m / s^{2}]$

When lift is at rest
$N = m g$
$\Rightarrow 60 \times 10 = 600 N$
When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction

$N^{'} = M (g - a)$
$\Rightarrow 60 (10 - 1.8)$
$N^{'} \Rightarrow 492 N$