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Q. A person standing on a spring balance inside a stationary lift measures $60 \,kg$. The weight of that person if the lift descends with uniform downward acceleration of $1.8 m / s ^{2}$ will be $N$. $\left[ g =10 m / s ^{2}\right]$

JEE MainJEE Main 2021Motion in a Straight Line

Solution:

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When lift is at rest
$N = mg$
$\Rightarrow 60 \times 10=600 \,N$
When lift moves with downward acceleration. In frame of lift pseudo force will be in upward direction
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$N ^{\prime}= M ( g - a )$
$\Rightarrow 60(10-1.8)$
$N ^{\prime} \Rightarrow 492\, N$