A person in an elevator accelerating upwards with an acceleration of 2ms- 2 , tosses a coin vertically upwards with a speed of 20ms- 1 . After how much time will the coin fall back into his hand? (g = 10ms- 2 )

Question

A person in an elevator accelerating upwards with an acceleration of 2ms- 2 , tosses a coin vertically upwards with a speed of 20ms- 1 . After how much time will the coin fall back into his hand? (g = 10ms- 2 ) (A) (5/3)s (B) (3/10)s (C) (10/3)s (D) (3/5)s

Tardigrade Admin · Accepted Answer

∴ t=(2 v/a + g)=(2 × 20 m s- 1/(. 2 + 10 .) m s- 2)=(40/12)s=(10/3)s

Q. A person in an elevator accelerating upwards with an acceleration of $2 m s^{- 2}$ , tosses a coin vertically upwards with a speed of $20 m s^{- 1}$ . After how much time will the coin fall back into his hand? (g = $10 m s^{- 2}$ )

$\frac{5}{3} s$

$\frac{3}{10} s$

$\frac{10}{3} s$

$\frac{3}{5} s$

$∴ t = \frac{2 v}{a + g} = \frac{2 \times 20 m s ^{- 1}}{( 2 + 10 ) m s ^{- 2}} = \frac{40}{12} s = \frac{10}{3} s$

Q. A person in an elevator accelerating upwards with an acceleration of 2ms−2 , tosses a coin vertically upwards with a speed of 20ms−1 . After how much time will the coin fall back into his hand? (g = 10ms−2 )

35​s

103​s

310​s

53​s