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  4. A person in an elevator accelerating upwards with an acceleration of 2ms- 2 , tosses a coin vertically upwards with a speed of 20ms- 1 . After how much time will the coin fall back into his hand? (g = 10ms- 2 )

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Q. A person in an elevator accelerating upwards with an acceleration of $2ms^{- 2}$ , tosses a coin vertically upwards with a speed of $20ms^{- 1}$ . After how much time will the coin fall back into his hand? (g = $10ms^{- 2}$ )

NTA AbhyasNTA Abhyas 2020

Solution:

$\therefore t=\frac{2 v}{a + g}=\frac{2 \times 20 m s^{- 1}}{\left(\right. 2 + 10 \left.\right) m s^{- 2}}=\frac{40}{12}s=\frac{10}{3}s$