A pendulum suspended from the roof of an elevator at rest has a time period T1, when the elevator moves up with an acceleration a its time period becomes T2, when the elevator moves down with an acceleration a, its time period becomes T3, then

Question

A pendulum suspended from the roof of an elevator at rest has a time period T1, when the elevator moves up with an acceleration a its time period becomes T2, when the elevator moves down with an acceleration a, its time period becomes T3, then (A) T1=√(T2 T3) (B) T1=√(T22+T32) (C) T1=(√2 T2 T3/√T22+T32) (D) none of these

Tardigrade Admin · Accepted Answer

Correct answer is (c) T1=(√2 T2 T3/√T22+T32)

Q. A pendulum suspended from the roof of an elevator at rest has a time period $T_{1}$ , when the elevator moves up with an acceleration $a$ its time period becomes $T_{2}$ , when the elevator moves down with an acceleration $a$ , its time period becomes $T_{3}$ , then

$T_{1} = (T_{2} T_{3})$

$T_{1} = (T_{2}^{2} + T_{3}^{2})$

$T_{1} = \frac{2 T _{2} T _{3}}{T _{2}^{2} + T _{3}^{2}}$

none of these

Correct answer is (c) $T_{1} = \frac{2 T _{2} T _{3}}{T _{2}^{2} + T _{3}^{2}}$

Q. A pendulum suspended from the roof of an elevator at rest has a time period T1​, when the elevator moves up with an acceleration a its time period becomes T2​, when the elevator moves down with an acceleration a, its time period becomes T3​, then

T1​=(T2​T3​)​

T1​=(T22​+T32​)​

T1​=T22​+T32​​2​T2​T3​​