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Q. A pendulum suspended from the roof of an elevator at rest has a time period $T_{1}$, when the elevator moves up with an acceleration $a$ its time period becomes $T_{2}$, when the elevator moves down with an acceleration $a$, its time period becomes $T_{3}$, then

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Solution:

Correct answer is (c) $T_{1}=\frac{\sqrt{2} T_{2} T_{3}}{\sqrt{T_{2}^{2}+T_{3}^{2}}}$