A passenger is walking on an escalator at a speed of 6 km / hrelative to the escalator. The escalator is moving at 3 km / h relative to ground and has a total length of 120 m. The time taken by him to reach the end of the escalator is

Question

A passenger is walking on an escalator at a speed of 6 km / hrelative to the escalator. The escalator is moving at 3 km / h relative to ground and has a total length of 120 m. The time taken by him to reach the end of the escalator is (A) 16 s (B) 48 s (C) 32 s (D) 80 s

Tardigrade Admin · Accepted Answer

Velocity of the passenger with respect to ground vP G=vP E+vE G=6+3=9 km / h Time taken, t=(x/vP G) =(120 m /9 × (5)18 m / s ) =(240/5) s =48 s

Q. A passenger is walking on an escalator at a speed of 6 km / hrelative to the escalator. The escalator is moving at 3 km / h relative to ground and has a total length of 120 $m$ . The time taken by him to reach the end of the escalator is

16 s

48 s

32 s

80 s

Velocity of the passenger with respect to ground
$v_{PG} = v_{PE} + v_{EG} = 6 + 3 = 9 km / h$
Time taken, $t = \frac{x}{v _{PG}}$
$= \frac{120 m}{9 \times \frac{5}{18} m / s}$
$= \frac{240}{5} s = 48 s$

Q. A passenger is walking on an escalator at a speed of 6 km / hrelative to the escalator. The escalator is moving at 3 km / h relative to ground and has a total length of 120 m. The time taken by him to reach the end of the escalator is