A particular reaction has a negative value for the free energy change. Then at ordinary temperature

Question

A particular reaction has a negative value for the free energy change. Then at ordinary temperature (A) it has a large negative value for the entropy change (B) it has a large positive value for enthalpy change (C) it has small positive value for enthalpy change (D) it has a positive value for the entropy change and a negative value for the enthalpy change

Tardigrade Admin · Accepted Answer

Since Δ G=Δ H-T Δ S, for a negative value of Δ G, at ordinary temperature, Δ H should be negative and Δ S should be positive.

Q. A particular reaction has a negative value for the free energy change. Then at ordinary temperature

it has a large negative value for the entropy change

it has a large positive value for enthalpy change

it has small positive value for enthalpy change

it has a positive value for the entropy change and a negative value for the enthalpy change

Since $Δ G = Δ H - T Δ S,$ for a negative value of $Δ G,$ at ordinary temperature, $Δ H$ should be negative and $Δ S$ should be positive.

Q. A particular reaction has a negative value for the free energy change. Then at ordinary temperature

it has a large negative value for the entropy change

it has a large positive value for enthalpy change

it has small positive value for enthalpy change

it has a positive value for the entropy change and a negative value for the enthalpy change

Since ΔG=ΔH−TΔS, for a negative value of ΔG, at ordinary temperature, ΔH should be negative and ΔS should be positive.

Since $Δ G = Δ H - T Δ S,$ for a negative value of $Δ G,$ at ordinary temperature, $Δ H$ should be negative and $Δ S$ should be positive.