1. Tardigrade
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  3. Chemistry
  4. A particular reaction has a negative value for the free energy change. Then at ordinary temperature

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Q. A particular reaction has a negative value for the free energy change. Then at ordinary temperature

Thermodynamics

Solution:

Since $\Delta G=\Delta H-T \Delta S,$ for a negative value of $\Delta G,$ at ordinary temperature, $\Delta H$ should be negative and $\Delta S$ should be positive.