A particle starts moving along a circle of radius ((40/π ))m with a constant tangential accleration. If the velocity of the particle is 120m/s at the end of the second revolution after the motion has begun, the tangential acceleration is

Question

A particle starts moving along a circle of radius ((40/π ))m with a constant tangential accleration. If the velocity of the particle is 120m/s at the end of the second revolution after the motion has begun, the tangential acceleration is (A) 40m/s2 (B) 35m/s2 (C) 45m/s2 (D) 50m/s2

Tardigrade Admin · Accepted Answer

vf2-ui2=2(R α )4π (120)2=2aT4π (40/π ) aT=(120 × 120/2 × 4 × 40) =45m/s2

Q. A particle starts moving along a circle of radius $(\frac{40}{π}) m$ with a constant tangential accleration. If the velocity of the particle is $120 m / s$ at the end of the second revolution after the motion has begun, the tangential acceleration is

$40 m / s^{2}$

$35 m / s^{2}$

$45 m / s^{2}$

$50 m / s^{2}$

$v_{f}^{2} - u_{i}^{2} = 2 (R α) 4 π$
$(120)^{2} = 2 a_{T} 4 π \frac{40}{π}$
$a_{T} = \frac{120 \times 120}{2 \times 4 \times 40}$
$= 45 m / s^{2}$

Q. A particle starts moving along a circle of radius (π40​)m with a constant tangential accleration. If the velocity of the particle is 120m/s at the end of the second revolution after the motion has begun, the tangential acceleration is

40m/s2

35m/s2

45m/s2

50m/s2