Question

A particle starts moving along a circle of radius $\left(\frac{40}{\pi }\right)m$ with a constant tangential accleration. If the velocity of the particle is $120m/s$ at the end of the second revolution after the motion has begun, the tangential acceleration is

• A. $40m/s^{2}$
• B. $35m/s^{2}$
• C. $45m/s^{2}$
• D. $50m/s^{2}$

Answer 1

Answer: (C)

$v_{f}^{2}-u_{i}^{2}=2\left(R \alpha \right)4\pi $
$\left(120\right)^{2}=2a_{T}4\pi \frac{40}{\pi }$
$a_{T}=\frac{120 \times 120}{2 \times 4 \times 40}$
$=45m/s^{2}$