A particle starts from rest and undergoes an acceleration as shown in figure. The velocity-time graph from figure will have a shape

Question

A particle starts from rest and undergoes an acceleration as shown in figure. The velocity-time graph from figure will have a shape (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Till t = 2 s, there is constant acceleration a m/s2 and after that there is constant deceleration - a m/s2 same magnitude. So velocity first increases from 0 to maximum and finally becomes zero.

Q. A particle starts from rest and undergoes an acceleration as shown in figure. The velocity-time graph from figure will have a shape

Till $t = 2 s$ , there is constant acceleration $a m / s^{2}$ and after that there is constant deceleration $- a m / s^{2}$ same magnitude. So velocity first increases from $0$ to maximum and finally becomes zero.

Q. A particle starts from rest and undergoes an acceleration as shown in figure. The velocity-time graph from figure will have a shape

Till t=2s, there is constant acceleration am/s2 and after that there is constant deceleration −am/s2 same magnitude. So velocity first increases from 0 to maximum and finally becomes zero.

Till $t = 2 s$ , there is constant acceleration $a m / s^{2}$ and after that there is constant deceleration $- a m / s^{2}$ same magnitude. So velocity first increases from $0$ to maximum and finally becomes zero.