Question

A particle starting from rest with uniform acceleration travels a distance $x$ in first $2$ second and a distance $y$ in next $2$ second, then

• A. $y=2x$
• B. $y=3x$
• C. $y=4x$
• D. $y=x$

Answer 1

Answer: (B)

Here $u=0$ For $t=2s,s=x$
Using $s=ut+\frac{1}{2}a{t}^2$
$x=\frac{1}{2}a\times 2^2=2a$
Next $2s$, the particle travels $y$
$\Rightarrow t=(2+2)s=4s,s=x+y$
$\Rightarrow (x+y)=\frac{1}{2}a(4{)}^2=8a$
$\Rightarrow (x+y)-x=8a-2a=6a$
or$y=6a=3(2a)\Rightarrow y=3x$