A particle of mass m oscillates with simple harmonic motion between points x1 and x2 the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph

Question

A particle of mass m oscillates with simple harmonic motion between points x1 and x2 the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

Potential energy of particle performing SHM is given by: PE=(1/2)mω 2y2 i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.

Q. A particle of mass m oscillates with simple harmonic motion between points $x_{1}$ and $x_{2}$ the equilibrium position being $O .$ Its potential energy is plotted. It will be as given below in the graph

Potential energy of particle performing SHM is given by: $PE = \frac{1}{2} m ω^{2} y^{2}$ i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.

Q. A particle of mass m oscillates with simple harmonic motion between points x1​ and x2​ the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph

Potential energy of particle performing SHM is given by: PE=21​mω2y2 i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.

Q. A particle of mass m oscillates with simple harmonic motion between points $x_{1}$ and $x_{2}$ the equilibrium position being $O .$ Its potential energy is plotted. It will be as given below in the graph

Potential energy of particle performing SHM is given by: $PE = \frac{1}{2} m ω^{2} y^{2}$ i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.